z^2-4z+10=z(z-5)

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Solution for z^2-4z+10=z(z-5) equation:


Simplifying
z2 + -4z + 10 = z(z + -5)

Reorder the terms:
10 + -4z + z2 = z(z + -5)

Reorder the terms:
10 + -4z + z2 = z(-5 + z)
10 + -4z + z2 = (-5 * z + z * z)
10 + -4z + z2 = (-5z + z2)

Add '-1z2' to each side of the equation.
10 + -4z + z2 + -1z2 = -5z + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
10 + -4z + 0 = -5z + z2 + -1z2
10 + -4z = -5z + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
10 + -4z = -5z + 0
10 + -4z = -5z

Solving
10 + -4z = -5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '5z' to each side of the equation.
10 + -4z + 5z = -5z + 5z

Combine like terms: -4z + 5z = 1z
10 + 1z = -5z + 5z

Combine like terms: -5z + 5z = 0
10 + 1z = 0

Add '-10' to each side of the equation.
10 + -10 + 1z = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 1z = 0 + -10
1z = 0 + -10

Combine like terms: 0 + -10 = -10
1z = -10

Divide each side by '1'.
z = -10

Simplifying
z = -10

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